折腾:
【已解决】如何判断某个经纬度位置在某个位置点的某个直径范围内
期间,需要去搞清楚,如何计算两个经纬度的点之间的距离,且需要在Python中实现出来。
经度 纬度 两点判断 距离
| private const double EARTH_RADIUS = 6378.137;//地球半径 private static double rad(double d) {    return d * Math.PI / 180.0; } public static double GetDistance(double lat1, double lng1, double lat2, double lng2) {    double radLat1 = rad(lat1);    double radLat2 = rad(lat2);    double a = radLat1 – radLat2;    double b = rad(lng1) – rad(lng2);    double s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a/2),2) +     Math.Cos(radLat1)*Math.Cos(radLat2)*Math.Pow(Math.Sin(b/2),2)));    s = s * EARTH_RADIUS;    s = Math.Round(s * 10000) / 10000;    return s; } | 
| /**     * google maps的脚本里代码     */       private const double EARTH_RADIUS = 6378.137;    private static double rad(double d)    {         return d * Math.PI / 180.0;    }     /**     * 根据两点间经纬度坐标(double值),计算两点间距离,单位为米     */    public static double GetDistance(double lat1, double lng1, double lat2, double lng2)    {        double radLat1 = rad(lat1);        double radLat2 = rad(lat2);        double a = radLat1 – radLat2;        double b = rad(lng1) – rad(lng2);        double s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a/2),2) +        Math.Cos(radLat1)*Math.Cos(radLat2)*Math.Pow(Math.Sin(b/2),2)));        s = s * EARTH_RADIUS;        s = Math.Round(s * 10000) / 10000;        return s;    }    | 
mysql 下 计算 两点 经纬度 之间的距离 计算结果排序 – 静下心来写代码 – 博客频道 – CSDN.NET
python latitude longitude distance
Calculate distance between latitude longitude pairs with Python · GitHub
| #!/usr/bin/env python # Haversine formula example in Python # Author: Wayne Dyck import math def distance(origin, destination):     lat1, lon1 = origin     lat2, lon2 = destination     radius = 6371 # km     dlat = math.radians(lat2-lat1)     dlon = math.radians(lon2-lon1)     a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1)) \         * math.cos(math.radians(lat2)) * math.sin(dlon/2) * math.sin(dlon/2)     c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))     d = radius * c     return d | 
Haversine Formula in Python (Bearing and Distance between two GPS points) – Stack Overflow
| from math import radians, cos, sin, asin, sqrt def haversine(lon1, lat1, lon2, lat2):     “””     Calculate the great circle distance between two points      on the earth (specified in decimal degrees)     “””     # convert decimal degrees to radians      lon1, lat1, lon2, lat2 = map(radians, [lon1, lat1, lon2, lat2])     # haversine formula      dlon = lon2 – lon1      dlat = lat2 – lat1      a = sin(dlat/2)**2 + cos(lat1) * cos(lat2) * sin(dlon/2)**2     c = 2 * asin(sqrt(a))      r = 6371 # Radius of earth in kilometers. Use 3956 for miles     return c * r | 
| pip install gpxpy –user import gpxpy.geo # Point one lat1 = 52.2296756 lon1 = 21.0122287 # Point two lat2 = 52.406374 lon2 = 16.9251681 # What you were looking for dist = gpxpy.geo.haversine_distance(lat1, lon1, lat2, lon2) print(dist) | 
geopy 1.11.0 : Python Package Index
【总结】
最后用代码:
| from math import radians, cos, sin, asin, sqrt ### calculate distance of two point # http://stackoverflow.com/questions/4913349/haversine-formula-in-python-bearing-and-distance-between-two-gps-points #def haversine(lon1, lat1, lon2, lat2): def calcDistance(lon1, lat1, lon2, lat2):     “””     Calculate the great circle distance between two points     on the earth (specified in decimal degrees)     “””     # convert decimal degrees to radians     lon1, lat1, lon2, lat2 = map(radians, [lon1, lat1, lon2, lat2])     # haversine formula     dlon = lon2 – lon1     dlat = lat2 – lat1     a = sin(dlat/2)**2 + cos(lat1) * cos(lat2) * sin(dlon/2)**2     c = 2 * asin(sqrt(a))     EARTH_RADIUS = 6371 # Radius of earth in kilometers. Use 3956 for miles     return c * EARTH_RADIUS | 
然后可以计算出两点之间的距离。
比如:
|             calculatedDistance = calcDistance(  curUser.location.longitude,                                                 curUser.location.latitude,                                                 eachUserLocation.longitude,                                                 eachUserLocation.latitude)             gLog.debug(“curUser.location=%s, eachUserLocation=%s -> calculatedDistance=%s”,                        curUser.location, eachUserLocation, calculatedDistance) | 
输出:
| curUser.location=<Location:id=location-c71da291-bd83-4292-9f54-e7baa46ac32f,createdAt=2016-11-06 11:58:38,updatedAt=2016-11-06 12:02:10,longitude=31.2764,latitude=120.739,shortStr=南京大学苏州研究生院,fullStr=江苏省苏州市吴中区仁爱路42号南京大学苏州研究生院>, eachUserLocation=<Location:id=location-4a7cd6e8-ded6-4777-aa90-6756f8c5f1b0,createdAt=2016-11-04 15:59:47,updatedAt=2016-11-06 12:03:34,longitude=31.2741,latitude=120.743,shortStr=GIST国际学院,fullStr=江苏省苏州市吴中区高博软件技术学院全球技术支持中心联合教育中心GIST国际学院> -> calculatedDistance=0.463593304637 | 
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